Question

A converging lens (f1 = 12.5 cm) is located 28.8 cm to the left of a diverging lens (f2 = -6.18 cm). A postage stamp is placed 36.9 cm to the left of the converging lens. Locate the final image of the stamp relative to the diverging lens.

Answer 1

The final image relative to the diverging lens at 9.0 cm.

Step-by-step explanation:

Given that,

Focal length of diverging lens = -6.18 cm

Focal length of converging lens = 12.5 cm

Distance of object = 36.9 cm

We need to calculate the image distance of converging lens

Using formula of lens

`(1)/(v)=(1)/(f)-(1)/(u)`

`(1)/(v)=(1)/(12.5)-(1)/(-36.9)`

`(1)/(v)=(988)/(9225)`

`v=9.33\ cm`

We need to calculate the image distance of diverging lens

Now, object distance is

`u=28.8-9.33=19.47 cm`

Using formula of lens

`(1)/(v)=(1)/(-6.18)-(1)/(-19.47)`

`(1)/(v)=-(22150)/(200541)`

`v=-9.0\ cm`

The image is formed 9.0 cm to the left of the diverging lens.

Hence, The final image relative to the diverging lens at 9.0 cm.