Question

A slice of pizza has 500 kcal. If we could burn the pizza and use all the heat to warm a 50-L container of cold water, what would be the approximate increase in the temperature of the water? ( Note: A liter of cold water weighs about 1 kg.)

Answer 1

10°C

Step-by-step explanation:

Heat gain by water = Heat lost by the slice of pizza

Thus,

`m_(water)* C_(water)* \Delta T=Q`

For water:

Volume = 50.0 L

Density of water= 1 kg/L

So, mass of the water:

`Mass\ of\ water=Density * {Volume\ of\ water}`

`Mass\ of\ water=1 kg/L * {50.0\ L}`

Mass of water = 50 kg

Specific heat of water = 1 kcal/kg°C

ΔT = ?

For slice of pizza:

Q = 500 kcal

So,

`50* 1* \Delta T=500`

ΔT = 10°C

Increase in temperature = 10°C