Question

How strong is the attractive force between a glass rod with a 0.700μC0.700μC charge and a silk cloth with a –0.600μC–0.600μC charge, which are 12.0 cm apart, using the approximation that they act like point charges?

Answer 1

0.2625 N/C

Step-by-step explanation:

Force of attraction =
`(K*Q_1* Q_2)/(R^2)`

where Q₁ and Q₂ are charges and R is distance between charges.K is a constant equal to 9 x 10⁹.

=
`(9*10^9*.7*10^(-6)*.6*10^(-6))/((12*10^(-2))^2)`

= 0.2625 N/C