What is the point of a horizontal tangent line to the function f(x)=(x^2-5) (x^2+5)

AlbertoFdzM asked Jun 15, 2023

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9 votes

What is the point of a horizontal tangent line to the function
f(x)=(x^2-5) (x^2+5)

AlbertoFdzM asked Jun 15, 2023

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17 votes

Answer: y=-25

When f(x)=(x^2-5)(x^2+5) y equals-25

Safl answered Jun 18, 2023

by Safl

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