Question

write an equation for the line that is parallel to the given line ans that passes through the given point: y=5/2x-10;(-6,-29)

Answer 1

all work is shown and pictured

Answer 2

`y=(5)/(2)x-14`

Explanation:

We are asked to write equation that is parallel to
`y=(5)/(2)-10` and passes through point
`(-6,-29)`.

We know that parallel lines have same slope, so the slope of parallel line would be
`(5)/(2)`.

Now, we will substitute
`m=(5)/(2)` and coordinates of point
`(-6,-29)` in slope-intercept form of equation as:

`y=mx+b`

`-29=(5)/(2)(-6)+b`

`-29=5(-3)+b`

`-29=-15+b`

`-29+15=-15+15+b`

`-14=b`

Therefore, our required equation would be
`y=(5)/(2)x-14`.