Question

A model rocket accelerates upward from the ground with a constant acceleration, reaching a height of 50 m in 8 s.a) What is the speed (in m/s) at a height of 50 m?A: 1.07×101 B: 1.25×101 C: 1.46×101 D: 1.71×101 E: 2.00×101 b) What is the acceleration (in m/s 2)?A: 1.56 B: 1.83 C: 2.14 D: 2.50 E: 2.93

Answer 1

Step-by-step explanation:

It is given that, a model rocket accelerates upward from the ground with a constant acceleration, u = 0

Height reached, d = 50 m

Time taken, t = 8 s

Let a is the acceleration of the rocket. It can be calculated using second equation of motion as,

`d=ut+(1)/(2)at^2`

`a=(2d)/(t^2)`

`a=(2* 50)/(8^2)`

`a=1.56\ m/s^2`

Let v is the speed at the height of 50 meters. So,

`v=u+at`

`v=at`

`v=1.56* 8`

v = 12.48 m/s

or
`v=1.25* 10^1\ m/s`

Hence, this is the required solution.