Question

The nonreflective coating on a camera lens with an index of refraction of 1.23 is designed to minimize the reflection of 544-nm light. If the lens glass has an index of refraction of 1.56, what is the minimum thickness of the coating that will accomplish this task?

Answer 1

Thickness = 110.57 nm

Step-by-step explanation:

Given that:

The refractive index of the lens = 1.56

The refractive index of the non reflecting coating = 1.23

The wavelength of the light = 544 nm

The thickness can be calculated by using the formula shown below as:

`Thickness=\frac {\lambda}{4* n}`

Where, n is the refractive index of the non reflecting coating = 1.23

`{\lambda}` is the wavelength

So, thickness is:

`Thickness=\frac {544\ nm}{4* 1.23}`

Thickness = 110.57 nm