115k views
5 votes
Each person attending a fund-raising party for a certain club was charged the same admission fee. How many people attended the party?

(1) If the admission fee had been $0.75 less and 100 more people had attended, the club would have received the same amount in admission fees.
(2) If the admission fee had been $1.50 more and 100 fewer people had attended, the club would have received the same amount in admission fees.

1 Answer

4 votes

Answer:

Let a = admission fee

Let n = number of people who attended the party

(1) If the admission fee had been $0.75 less and 100 more people attended, the club would have received the same amount in admission fees.


an=(a -0.75)(n+100)


an =an-0.75n+100a-75


0.75n-100a =-75 ...(1)

(2) If the admission fee had been $1.50 more and 100 fewer people had attended, the club would have received the same amount in admission fees.


an=(a+1.50)(n-100)


an= an+1.5n-100a-150


1.5n-100a= 150 ......(2)

Subtracting (1) from (2) we get


0.75n=225

n = 300

And substituting n = 300 to get value of a;


1.5(300)-100a= 150


450-100a=150
-100a=-450+150


100a=300

a = 3

Hence, $3 was admission fee and 300 people attended the party.

User Mloning
by
7.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories