Question

Consider this system of equations. Which equation represents the first equation written in slope-intercept form?

5X-2Y=10
Y=1/4X+1

A. Y=5/2X-5
B. Y=5/2X+10
C. Y=-5/2X+10
D. Y=-5X-5

Answer 1

A. Y = 5/2x - 5.

Explanation:

5X - 2Y = 10

-2Y = -5X + 10

Divide both sides by -2:

Y = 5/2x - 5.

Answer 2

Answer: A. 5/2 X - 5

Explanation:

5x - 2y =10

To write the equation in a slope intercept we have to make y subject of the formular

5x - 2y = 10

we will take 2y to the right-handside and 10 to the left-handside

5x-10 = 2y

2y = 5x - 10

we divide bothside by 2

2y/2 = 5x/2 - 10/2

y = 5/2 X - 10