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A sample of oxygen gas at a pressure of 1.05 atm and a temperature of 177°C, occupies a volume of 792 mL. If the gas is heated at constant pressure until its volume is 1.05×103 mL, the temperature of the gas sample will be - °C

User Giacomoni
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9 votes

Answer:

235 °C

Step-by-step explanation:

Since the pressure is being held constant, you can use Charles' Law to find the final temperature:

V₁ / T₁ = V₂ / T₂

In this equation, "V₁" and "T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature. You can plug the given values into the equation and simplify to find "T₂". The final answer should have 3 sig figs like the given values.

V₁ = 792 mL V₂ = 1.05 x 10³ mL

T₁ = 177 °C T₂ = ? °C

V₁ / T₁ = V₂ / T₂ <----- Charles' Law

792 mL / 177 °C = 1.05 x 10³ mL / T₂ <----- Insert values

4.4746 = 1.05 x 10³ mL / T₂ <----- Simplify left side

(4.4746) x T₂ = 1.05 x 10³ mL <----- Multiply both sides by T₂

T₂ = 235 <----- Divide both sides by 4.4746

User Yoav Aharoni
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