92.7k views
2 votes
15. Use your knowledge of fractional exponents to show that the following

statement is true: The square root of the cube root of a number equals
the sixth root of that number.

User Shiju
by
5.2k points

2 Answers

5 votes

Answer:

Step-by-step explanation:

((X)^1/2 )^1/3 = x^(1/2 ×1/3)= x^1/6

that what you need to prove

User ANAS AJI MUHAMMED
by
5.2k points
6 votes

Final answer:

The square root of the cube root of a number equals the sixth root because when you raise a power to another power (in this case, (x^(1/3))^(1/2)), you multiply the exponents, resulting in x^(1/6), which represents the sixth root of a number.

Step-by-step explanation:

Understanding Fractional Exponents in Mathematics

To show that the square root of the cube root of a number equals the sixth root of that number, let us use fractional exponents. Considering a number x, the cube root of x is represented as x1/3.

The square root of the cube root of x would then be (x1/3)1/2. According to the properties of exponents, when raising a power to another power, you multiply the exponents. Thus,

(x1/3)1/2 = x1/3 × 1/2 = x1/6,

which is precisely the sixth root of x. This demonstration uses the general exponential rule that (am)n = am × n, as illustrated in previous examples with different bases and exponents.

User Makram
by
5.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.