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Solve for x. Find the angle measures. Angle AOB=x+3, angle AOC=2x+11, angle BOC=4x-7

Solve for x. Find the angle measures. Angle AOB=x+3, angle AOC=2x+11, angle BOC=4x-example-1
User Pizza
by
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2 Answers

4 votes

Answer:

x=5


\angle AOC=21


\angle AOB=8


\angle BOC=13

Explanation:

We are given that


\angle AOB=x+3


\angle AOC=2x+11


\angle BOC=4x-7

We have to solve for x and find the angle measures


\angle AOC=\angle AOB+\angle BOC


2x+11=x+3+4x-7


2x+11=5x-4


11+4=5x-2x


15=3x


x=(15)/(3)=5

Substitute the value of x then, we get


\angle AOC=2(5)+11=21


\angle AOB=5+3=8


\angle BOC=4(5)-7=13

User Justin O Barber
by
8.0k points
4 votes

Answer:

x=5

AOB = 8

BOC = 13

AOC = 21

Explanation:

Angle AOB and Angle BOC is equal to Angle AOC.

AOB = x+3

BOC = 4x-7

AOC= 2x+11

AOB + BOC = AOC

x+3+4x-7 = 2x+11

5x-4 = 2x+11

3x = 15

x = 5

Therefore, the value of x is 5.

Angle AOB = x+3

AOB = 5+3

AOB = 8

Angle BOC = 4x-7

BOC = 4(5)-7

BOC = 13

Angle AOC = 2x+11

AOC = 2(5)+11

AOC = 21

!!

User Jaffa
by
7.1k points