Question

Find the midpoint of diagonal AC of ABCD

Answer 1

M= (1, 3)

Explanation:

we have from the picture:

A = (-3,5)

C = (5, 1)

M = Midpoint

M =((x1+x2)/2), ((y1+y2)/2)

so we have:

x1= -3 y1 = 5

x2= 5 y2= 1

M= ((-3+5)/2) , ((5+1)/2)

M = ((2/2) , (6/2))

M= (1, 3)