Question

Q 30.27: The nucleus of the hydrogen atom has a radius of about 1.2 x 10-15 m. The electron is normally at a distance of about 5.3 x 10-11 m. Assume that the hydrogen atom is a uniform sphere of radius 5.3 x 10-11 m. What percentage of the volume of the atom is occupied by the nucleus?

Answer 1

`1.1606* 10^(-12) \%` is the percentage of the volume of the atom is occupied by the nucleus.

Step-by-step explanation:

Radius of the nucleus of the hydrogen atom,
`r_n=1.2* 10^(-15) m`

Radius of the hydrogen atom =
`r=5.3* 10^(-11) m`

Volume of hydrogen atom ,V=
`(4)/(3)\pi r^3`

`V=(4)/(3)\pi r^3`

Volume of nucleus of hydrogen atom ,
`V_n=(4)/(3)\pi r_(n)^3`

`V_n=(4)/(3)\pi r_(n)^3`

Percentage of the volume of the atom is occupied by the nucleus:

`(V_n)/(V)* 100`

`((4)/(3)\pi r_(n)^3)/((4)/(3)\pi r^3)* 100`

`=1.1606* 10^(-12) \%`

`1.1606* 10^(-12) \%` is the percentage of the volume of the atom is occupied by the nucleus.