Question

A single-wavelength beam of light is pointed at a dark shield with two narrow slits. As a result, an interference pattern forms in the space on the other side of the partition. The wavelength is 635 nm, and the first-order bright fringe lies at a 16.6° angle from the central maximum. What is the slit separation (in µm)?

Answer 1

The slit separation is 2.2μm.

Step-by-step explanation:

Given that,

Wavelength = 635 nm

Angle = 16.6°

Order number = 1

We need to calculate the slit position

Using formula of slit distance

`d\sin\theta= m\lambda`

`d=(m\lambda)/(\sin\theta)`

Where,
`\lambda` = wavelength

m = order number

Put the value into the formula

`d=(1*635*10^(-9))/(\sin 16.6)`

`d=2.2*10^(-6)\ m`

`d=2.2\ \mu m`

Hence, The slit separation is 2.2μm.