Answer:
Step-by-step explanation:
Given
object distance u = 3 m (- ve)
Focal length f = .05 m ( + ve )
Lens formula ,
1 / v - 1 / u = 1 / f
1 / v + 1/3 = 1 / .05
1 / v = 1 / .05 - 1 / 3
1 / v = 20 -0 .333
= 19.667
v = 1 /19.667
v = .05 m = 5 cm.
magnification = v / u = .05 / 3
size of image = ( .05 / 3) x 1.75 = 2.9 cm.