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Which is the same solution a x2-16x+12 =0

User Driss Amri
by
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1 Answer

4 votes

Answer:

An equation which has the same solution as the given equation is:

( x - 18 ) ( x + 2 ) + 48 = 0 ....

Explanation:

The given expression is:

x2-16x+12

Break the constant term:

x^2-16x-36 +48=0

[x^2-16x-36] +48=0

Now break the middle term inside the brackets

(x^2-18x+2x-36)+48=0

Take the common

[x(x-18) +2(x-18)]+48=0

(x-18)(x+2)+48=0

Thus an equation which has the same solution as the given equation is:

( x - 18 ) ( x + 2 ) + 48 = 0 ....

User Mostafa Jamareh
by
5.5k points