In order to find the Perimeter of the Rectangle, First we need to find the Length and Width of the Rectangle.
Distance between two points (x₁ , y₁) and (x₂ , y₂) is given by :

There are two lengths in a rectangle. Let us find any one length of the rectangle.
I'm considering the length with co-ordinates (-8 , 2) and (-2 , 10)
Here : x₁ = -8 and x₂ = -2 and y₁ = 2 and y₂ = 10
Substituting the values in the distance formula, We get :
![\mathsf{\implies Length = √([-2 - (-8)]^2 + [10 - 2]^2)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vo7t1qdzulzfj4wx0h0luscgjcqyb6n524.png)
![\mathsf{\implies Length = √([-2 + 8]^2 + [8]^2)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ynuat0fheymgzi0m4jpv5jgguo1md5vs58.png)
![\mathsf{\implies Length = √([6]^2 + [8]^2)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/38vi1maa4417okm5oslnsxr801679sqmzi.png)



There are two widths in a rectangle. Let us find any one width of the rectangle.
I'm considering the width with co-ordinates (-2 , 10) and (2 , 7)
Here : x₁ = -2 and x₂ = 2 and y₁ = 10 and y₂ = 7
Substituting the values in the distance formula, We get :
![\mathsf{\implies Width = √([2 - (-2)]^2 + [7 - 10]^2)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/372ot4ya29wom78akcn5abyewkc47b6dn3.png)
![\mathsf{\implies Width = √([2 + 2]^2 + [-3]^2)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/aij11p6h75ccz1nezaiwvnsa6k4qty2lma.png)
![\mathsf{\implies Width = √([4]^2 + [-3]^2)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/banf3c6o2wvhhrfzzi0bbnkd9oxeskdmlv.png)



Perimeter of a Rectangle is given by : 2[Length + Width]
Perimeter of the given rectangle = 2[10 + 5]
Perimeter of the given rectangle = 2[15]
Perimeter of the given rectangle = 30
Answer : Perimeter of the given rectangle is 30 square units