Question

If r(x) = 3x – 1 and s(x) = 2x + 1, which expression is equivalent to (r/s)(6)?

Answer 1

For this case we have the following functions:

`r (x) = 3x-1\\s (x) = 2x + 1`

We must find (\ frac {r} {s}) (x)

By definition we have to:

`(\frac {r} {s}) (x) = \frac {r (x)} {s (x)}`

So:

`(\frac {r} {s}) (x) = \frac {3x-1} {2x + 1}`

We evaluate the function at
`x = 6`:

`(\frac {r} {s}) (6) = \frac {3 (6) -1} {2 (6) +1} = \frac {18-1} {12 + 1} = \frac {17 } {13}`

Answer:

`(\frac {r} {s}) (x) = \frac {17} {13}`