Question

Two small metal spheres are 25 cm apaft.The spheres have equal amount of negative charge and repel each other with a force of 0.036 N. What is the magnitude of the charge on each sphere? (a) 2x10-3 C (h) 3 x 10-4C

Answer 1

`0.5* 10^(-6)C`

Step-by-step explanation:

According to coulombs law force between two charges is given by
`F=(1)/(4\pi \epsilon _0)(Q_1Q_2)/(R^2)` here R is the distance between both the charges which is given as 25 cm

We have given force F =0.036 N

So
`0.036=(1)/(4\pi * 8.85* 10^(-12))(Q^2)/((0.25^2))` As
`\epsilon _0` is constant which value is
`8.85* 10^(-12)`

`Q^2=0.250* 10^(-12)`

`Q=0.5* 10^(-6)C`