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Find the length of an organ pipe closed at one end that produces a fundamental frequency of 256 Hz when air temperature is 18° c A. 0.167 m B.0.334 m C. 0.667 m O D. 1.336 m

User SioGabx
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1 Answer

7 votes

Answer:

B. 0.334 m

Step-by-step explanation:

Given that fundamental frequency of organ pipe which is closed at one end is,
f_(0)=256Hz

And the temperature of air is,
T=18^(\circ) C

Now convert temperature in kelvin,


T=(18+273)K\\T=291 K

Now the fundamental frequency formula when the organ pipe is open at one end.


f_(0) =(v)/(2L)

Here, v is the velocity of sound, L is the length of organ pipe.

For further solving it for L.


L=(v)/(4f_(0) )

And also we know that,


v=v_(0)\sqrt{(T)/(273) }

Here,
v_(0) is rthe speed of sound at room temperature and the value of this is,


v_(0)=331 km/s.

Now,


v=331\sqrt{(291)/(273) } \\v=331* 1.0324\\v=341.7373 m/s

Now put this value in L equation,


L=(341.7373)/(4* 256) \\L=0.3337 m\\L=0.334 m

Therefore, the length of an organ pipe is 0.334 m

User Arnold Ewin
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