Question

Find the range in nanometers of visible wavelengths of light in zircon (n = 1.923). (Assume visible light has wavelengths ranging from 380 nm to 760 nm in a vacuum.) shortest wavelength nm

longest wavelength nm

Answer 1

Step-by-step explanation:

It is given that,

Refractive index of zircon, n = 1.923

The wavelength of visible light ranging from 380 nm to 760 nm in a vacuum.

Wavelength 1,
`\lambda_1=380\ nm=380* 10^(-9)\ m`

Wavelength 2,
`\lambda_2=760\ nm=760* 10^(-9)\ m`

We need to find the shortest and longest wavelength. For shortest wavelength,
`\lambda_s=(\lambda_1)/(n)`

`\lambda_s=(380* 10^(-9))/(1.923)=1.97* 10^(-7)\ m`

For longest wavelength,
`\lambda_l=(\lambda_2)/(n)`

`\lambda_l=(760* 10^(-9))/(1.923)=3.95* 10^(-7)\ m`

Hence, this is the required solution.