Question

8. Referring to the metabolic process involving glucose, calculate the maximum number of moles of ATP that can be synthesized from ADP from the breakdown of one mole of glucose. (8 points) C6H12O6 + 6O2 → 6CO2 + 6H2O ΔGº = –2880 kJ/mol ADP + H3PO4 → ATP ΔGº = +31 kJ/mol

Answer 1

93 moles

Step-by-step explanation:

The breakdown of 1 mole of glucose is shown by the reaction shown below:

`C_6H_(12)O_6+6O_2\rightarrow 6CO_2+6H_2O\ \Delta G^0=-2880 kJ/mol`

It means that 1 mole of breakdown of glucose produces 2880 kJ of energy.

The reaction of the phosphorylation of ADP to ATP is shown below as:

`ADP+H_3PO_4\rightarrow ATP\ \Delta G^0=31 kJ/mol`

It means that 1 mole of ADP needs 31 kJ of energy to convert into 1 mole of ATP

Which also means that:

31 kJ of energy is required to form 1 mole of ATP from ADP

1 kJ of energy is required to form
`\frac {1}{31}` mole of ATP from ADP

2880 kJ of energy is required to form
`\frac {1}{31}* 2880` mole of ATP from ADP

Thus moles of ATP form ≅ 93 moles