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A coil of wire (61.163 cm^2 area) can generate a voltage difference when rotated in a magnetic field. If a 904 turn coil is rotated at 65 Hz in a B field of 0.001 T, what is the voltage created ?

1 Answer

3 votes

Answer:


EMF_(max) = 2.26 Volts

Step-by-step explanation:

As we know that the rotating coil will have change in the angle with time at all instant of time

so at any general instant of time we can say


\phi = NBA cos\omega t

now we have


EMF = (d\phi)/(dt)

so we have


EMF = NBA\omega sin\omega t

so we have maximum induced EMF in the coil is given as


EMF_(max) = NBA\omega


EMF_(max) = (2\pi f)NBA

N = 904 turns

B = 0.001 T


A = 61.163 cm^2 = 61.163 * 10^(-4) m^2

f = 65 Hz

now we have


EMF_(max) = (904)(0.001)(61.163 * 10^(-4))(2\pi* 65)


EMF_(max) = 2.26 Volts

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