Question

A hockey puck with a mass of 0.167 kg slides over the ice. The puck initially slides with a speed of 5.45 m/s, but it comes to a rough patch in the ice, which slows it down to a speed of 2.95 m/s. How much energy is dissipated as the puck slides over the rough patch?

Answer 1

The energy dissipated is 1.754 J.

Step-by-step explanation:

Given that,

Mass of hockey = 0.167 Kg

Initial velocity = 5.45 m/s

Finally velocity = 2.95 m/s

We need to calculate to the energy dissipated over the rough patch = loss in kinetic

`E_(d)=(1)/(2)m(v_(2)^2-v_(1)^2)`

Where, m = mass

`v_(1)` = Initial velocity

`v_(2)` = Final velocity

Put the value into the formula

`E_(d)=(1)/(2)*0.167*(2.95^2-5.45^2)`

`E_(d)=-1.7535\ J`

Negative sign shows the loss of energy.

Hence, The energy dissipated is 1.754 J.