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An 8-MeV neutron is inelastically scattered from a barium nucleus. What is the average energy of the emergent inelastic neutrons?

1 Answer

6 votes

Answer:

7.45 Mev

Step-by-step explanation:

in this case we need to considerated the following formula

alpha = E/Eo

where:

alpha = (A - 1)square /(A + 1)square

and A is the mass number of nucleus , for this case the Ba is 56

so we replace the values

alpha = (56 - 1)square /(56+ 1)square

alpha = 55²/57²

E = 8×55×55/57×57

E = 7.45 Mev

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