Question

At one point in space the Electric potential is measured to be 119 V at a distance of 1 meters away it is measured to be 43 V. Find the magnitude electric field.

Answer 1

76 V/m

Step-by-step explanation:

`V_(i)` = Electric potential at initial location = 119 V

`V_(f)` = Electric potential at final location = 43 V

`d` = distance between initial and final location = 1 m

`E` = magnitude of electric field

Magnitude of electric field is given as

`E = (- (V_(f) - V_(i)))/(d)`

`E = (- (43 - 119))/(1)`

`E` = 76 V/m