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an equation of a line that passes through the point (15,2) and is perpendicular to the line -10x+8y = 3?

User Frozenjim
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1 Answer

2 votes

Answer:

y = -⁴/₅x + 14

Explanation:

Changing to slope-intercept form:

-10x + 8y = 3 {add 10x to both sides}

8y = 10x + 3 {divide both sides by 8}

y = ⁵/₄x + ³/₈

Two lines are perpendicular if the product of their slopes is equal -1:

y=m₁x+b₁ ⊥ y=m₂x+b₂ ⇔ m₁×m₂ = -1

y = ⁵/₄x + ³/₈ ⇒ m₁=⁵/₄

⁵/₄×m₂ = -1 ⇒ m₂ = -⁴/₅

The line y=-⁴/₅x+b passes through point (15, 2) so the equation:

2 = -⁴/₅×15 + b must be true

2 = -12 + b

b = 14

Therefore equation in slope-intercept form:

y = -⁴/₅x + 14

User Mavrck
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6.6k points