Question

Light going from glass (index of refraction = 1.4) to ethanol has a critical angle of incidence of 65°. What is the index of refraction of ethanol?

Answer 1

1.27

Step-by-step explanation:

`n_(g)` = Index of refraction of glass = 1.4

`n_(e)` = Index of refraction of ethanol = ?

i = Angle of incidence = critical angle = 65° deg

r = Angle of refraction = 90° deg

Using Snell's law

`n_(g)` Sini =
`n_(e)` Sinr

(1.4) Sin65 =
`n_(e)` Sin90

`n_(e)` = 1.27