Question

In a double-slit experiment, the third-order maximum for light of wavelength 490 nm is located 15 mm from the central bright spot on a screen 1.6 m from the slits. Light of wavelength 670 nm is then projected through the same slits. How far from the central bright spot will the second-order maximum of this light be located?

Answer 1

The distance from the central bright spot are
`156.8*10^(-3)\ mm` and
`142.9*10^(-3)\ mm`.

Step-by-step explanation:

Given that,

Wavelength = 490 nm

Distance y= 15 mm

Length L=1.6 m

New wavelength = 670

We need to calculate the distance from the central bright spot

Using formula of distance

`y= (m\lambda L)/(d)`

`d=(m\lambda L)/(y)`

Put the value into the formula

`d=(3*490*10^(-9)*1.6)/(15*10^(-3))`

`d=156.8*10^(-6)\ m`

`d=156.8*10^(-3)\ mm`

We need to calculate the distance from the central bright spot for new wavelength

Using formula of distance

`d=(m\lambda L)/(y)`

Put the value into the formula

`d=(2*670*10^(-9)*1.6)/(15*10^(-3))`

`d=142.9*10^(-6) m`

`d=142.9*10^(-3)\ mm`

Hence, The distance from the central bright spot are
`156.8*10^(-3)\ mm` and
`142.9*10^(-3)\ mm`.