Question

(-4,-6) and (3,-7) find the distance between each pair of points

Answer 1

`5√(2)\approx 7.07` units.

Explanation:

We have been given coordinates of two points. We are asked to find the distance between both points.

We will use distance formula to solve our given problem.

`D=√((x_2-x_1)^2+(y_2-y_1)^2)`

Let point
`(-4,-6)=(x_1,y_1)` and point
`(3,-7)=(x_2,y_2)`.

`D=√((3-(-4))^2+(-7-(-6))^2)`

`D=√((3+4)^2+(-7+6)^2)`

`D=√((7)^2+(-1)^2)`

`D=√(49+1)`

`D=√(50)`

`D=√(25*2)`

`D=5√(2)`

`D=7.07`

Therefore, the distance between both points is
`5√(2)\approx 7.07` units.

Answer 2

`5√(2)`

Explanation:

distance between two points:

`d = \sqrt{(x_(2)-x_(1))^(2)+ (y_(2)-y_(1))^(2)}`

we have:

(-4, -6), (3, -7)

`x_(1) = -4`

`y_(1) =-6`

`x_(2) = 3`

`y_(2) =-7`

so we have:

`d =\sqrt{(3-(-4))^(2)+ (-7-(-6))^(2)}\\\\d =\sqrt{(7)^(2)+ (-1)^(2)}\\\\d = √(49+ 1)\\\\d=√(50)\\\\d=5√(2)`