Answer:
The rate of the boat in still water is 44 mph and the rate of the current is 4 mph
Step-by-step explanation:
x = the rate of the boat in still water
y = the rate of the current.
Distance travelled = 120 mi
Time taken upstream = 3 hr
Time taken downstream = 2.5 hr
Speed = Distance / Time
Speed upstream
![(120)/(3)=x-y\\\Rightarrow 40=x-y](https://img.qammunity.org/2020/formulas/physics/high-school/p9unph12excx5zxuxdgbp7whyhuxcuh6a3.png)
Speed downstream
![(120)/(2.5)=x+y\\\Rightarrow 48=x+y](https://img.qammunity.org/2020/formulas/physics/high-school/24b6osk6i6yhe55x98g41ofec12xhtm0jq.png)
Adding both the equations
![48+40=x-y+x+y\\\Rightarrow 88=2x\\\Rightarrow 44=x](https://img.qammunity.org/2020/formulas/physics/high-school/nge6hr95opxjonmd3zel98fat0pwickgsy.png)
![40=44-y\\\Rightarrow 40-44=-y\\\Rightarrow y=4](https://img.qammunity.org/2020/formulas/physics/high-school/rkaljerfjocmtvuuuu64rb6u8t4dm3sle0.png)
The rate of the boat in still water is 44 mph and the rate of the current is 4 mph