Answer:
0.01332
Explanation:
Given : On average, Bethany has noticed that 22 trains pass by her house daily (24 hours) on the nearby train tracks.
To Find :What is the probability that at most 4 trains will pass her house in a 6-hour time period
Solution:
We are suppose to find the probability that at most 4 trains will pass her house in a 6-hour time period
The probability that 0 train will pass her house in a 6-hour time period =
![(^(22)C_0)/(^(24)C_6)](https://img.qammunity.org/2020/formulas/mathematics/college/9cnqpv9q3b2upg9cg0v5f1kk13qnpfbsfz.png)
The probability that 1 train will pass her house in a 6-hour time period =
![(^(22)C_1)/(^(24)C_6)](https://img.qammunity.org/2020/formulas/mathematics/college/hnuf4fbwlynauqv36rn6ts9mycm3xiqe9r.png)
The probability that 2 train will pass her house in a 6-hour time period =
![(^(22)C_2)/(^(24)C_6)](https://img.qammunity.org/2020/formulas/mathematics/college/mfem2m4q2yvvwq3ladf8x098gkiwyx7zma.png)
The probability that 3 train will pass her house in a 6-hour time period =
![(^(22)C_3)/(^(24)C_6)](https://img.qammunity.org/2020/formulas/mathematics/college/h3jdv28h9wslbar5e3noxm4nfd0fuclxi7.png)
So, the probability that at most 4 trains will pass her house in a 6-hour time period =
![(^(22)C_0)/(^(24)C_6)+(^(22)C_1)/(^(24)C_6)+(^(22)C_2)/(^(24)C_6)+(^(22)C_3)/(^(24)C_6)](https://img.qammunity.org/2020/formulas/mathematics/college/w8xb2sc31nrkk9oimr7jxwko3iyr0kn87a.png)
=
![0.01332](https://img.qammunity.org/2020/formulas/mathematics/college/yh2o21hlf79u5dzgsc1u0r5dfaiv232wez.png)
Hence the probability that at most 4 trains will pass her house in a 6-hour time period is 0.01332