Question

Find the slope of the line that passes through each pair of points (-3/4,5),(5/4,2)

Answer 1

`\bf (\stackrel{x_1}{-(3)/(4)}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{(5)/(4)}~,~\stackrel{y_2}{2}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{5}}}{\underset{run} {\underset{x_2}{(5)/(4)}-\underset{x_1}{(-(3)/(4))}}}\implies \cfrac{-3}{(5)/(4)+(3)/(4)}\implies \cfrac{-3}{(5+3)/(4)}\implies\cfrac{-3}{(8)/(4)}\implies \cfrac{-3}{2}`

Answer 2

m=-3/2

Explanation:

m=slope

m = (y2-y1)/(x2-x1)

first point: (-3/4,5)

second point: (5/4,2)

m= (2-5)/(5/4-(-3/4))

m= -3/2