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A 75 kg runner taking part in a 200 m dash must run around the end of a track that has a circular arc with a radius of curvature of 32 meters. if he completes the 200 m dash in 20.33 s and runs at constant speed throughout the race, what is the magnitude of his centripetal force as he runs the curved portion of the track?

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Answer:

F= -226.7874N

Step-by-step explanation:

Initially we must determine the speed at which the runner runs that is given by the following equation:

v= velocity= (200m)/(20.33s) = 9.8377 m/s

To determine the centripetal force of the corridor in the curve we must use the following equation:

Fc= centripetal force= -m × ω² × r

m= mass of the runner

ω= angular speed

r= ratio of the curve

The angular velocity is the swept angle per unit of time, so we determine that perimeter has a complete turn of the curve, 2π radians, and calculate the time it would take to travel it to the runner to know the angular velocity it takes:

Perimeter= 2π × r= 2π × 32m= 201.0619m

The time it would take to travel would be:

t= (201.0619m / 9.8377 m/s)= 20.4379s

ω= (2π)/(20.4379s)= 0.3074 (rad/s)

After obtaining these values ​​we can calculate the centripetal force to which the runner is exposed in the curve:

F= - 75kg × (0.3074 rad/s)² × 32m= -226.7874N

The minus sign corresponds to the sense of force being outward of the radius of curvature.

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