Answer:
no. of electrons, n =
passes through his body
Step-by-step explanation:
We know the the rate of flow of charge is current and also amount of charge is an integral multiple of charge of an electron.
The two relations for current and charge are given as:

where
q = charge
I = current
t = time = 1 min = 60 s
So,
(1)
Also,
q = ne (2)
n = 0, 1, 2,.....
e = charge of an electron =
C
Using eqn (1) and (2):


n =
