Question

X=3-√5 find the value of √x+ 1/√x

Answer 1

`\bf x = 3-√(5) \\\\[-0.35em] ~\dotfill\\\\ √(x)+\cfrac{1}{√(x)}\implies (3-√(5))+\cfrac{1}{3-√(5)}\qquad \impliedby \textit{let use the LCD of }3-√(5) \\\\\\ \cfrac{(3-√(5))3-(3-√(5))√(5)+(1)1}{3-√(5)} \implies \cfrac{9-3√(5)-(3√(5)-5)+1}{3-√(5)} \\\\\\ \cfrac{9-3√(5)-3√(5)+5+1}{3-√(5)}\implies \cfrac{15-6√(5)}{3-√(5)}`