Question

A wheel accelerates uniformly from rest to a rotational speed of 10 rad/s in 5 s. What is its angular acceleration?

Answer 1

angular acceleration=
`2 (rad)/(s^(2) )`

Step-by-step explanation:

Kinematic equation for uniformly accelerated circular motion:

`wf=wi+\alpha *t`

wf=final angular speed
`((rad)/(s) )`

wi=initial angular speed
`((rad)/(s) )`

`\alpha`= angular acceleration
`((rad)/(s^(2) ) )`

We replace wf=10
`(rad)/(s)`,wi=0, t=5s in the equation(1):

`10=0+\alpha *5`

`\alpha =(10)/(5)`

`\alpha =2 (rad)/(s^(2) )`

The angular acceleration is 2
`(rad)/(s^(2) )`