Answer:
3w³ + 20w² + 39w + 18
Explanation:
It is given that,
(2 + 3w)(w² + 6w + 9)
To find the multiplication
(2 + 3w)(w² + 6w + 9) = 2 * w² + 2 * 6w + 2* 9 + 3w * w² +3w * 6w + 3w* 9
= 2w² + 12w + 18 + 3w³ + 18w² + 27w
= 3w³ + 20w² + 39w + 18
Therefore the final value = 3w³ + 20w² + 39w + 18