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He image of ΔABC after a reflection across is ΔA'B'C'.
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He image of ΔABC after a reflection across is ΔA'B'C'.

User Stragu
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2 votes

Answer:

Here is the photo

Explanation:

He image of ΔABC after a reflection across is ΔA'B'C'.-example-1
User David Peterson
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where is the "he image"

User Archit Verma
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