Question

Acceleration Practice

Find the acceleration of a horse that bolts out of the gate, starting at rest and reaches a velocity of 17 m/s in 20 sec.

Answer 1

0.85 m/s^2

Step-by-step explanation:

Acceleration = (final velocity - starting velocity) / time

Final velocity = 17

Starting velocity = 0

Time = 20

1. Substitute:

Acceleration = (starting velocity - final velocity) / time --> Acceleration = ( 17 - 0) / 20

2. Solve:

Acceleration = ( 17 - 0) / 20 -->

Acceleration = 0.85

Answer 2

0.85 m/s²

Step-by-step explanation:

Acceleration is change in velocity over change in time. In mathematically, it can be expressed as:

`\displaystyle{\vec{a} = \frac{\Delta \vec{v}}{\Delta t} = (\vec v_2 - \vec v_1)/(t_2-t_1)}`

Our final velocity is given to be 17 m/s in 20 seconds. Initial velocity is at starting point which is 0 m/s in 0 second. Therefore:

`\displaystyle{\vec{a} = \frac{\Delta \vec{v}}{\Delta t} = (17-0)/(20-0)}\\\\\displaystyle{\vec{a} = \frac{\Delta \vec{v}}{\Delta t} = (17)/(20)}\\\\\displaystyle{\vec{a} = \frac{\Delta \vec{v}}{\Delta t} = 0.85 \ \, \sf{m/s^2}}`

Therefore, the acceleration of a horse from starting point to 17 m/s in 20 seconds is 0.85 m/s²