Question

Mr.rodriguez invests half money in land a tenth in stocks and a twentieth in bonds he puts the remaining 35,000 in his savings account what is the total amount of money that Mr Rodriguez saves and invests

Answer 1

100000

Explanation:

Let total amount of money that Mr. Rodriguez saves and invests be x

Money invested in land =
`(x)/(2)`

Money invested in stocks =
`(x)/(10)`

Money invested in bonds =
`(x)/(20)`

Money in savings account = 35,000

According to question ,

Money invested in land + Money invested in stocks + Money invested in bonds + Money in savings account = Total amount of money that Mr. Rodriguez saves and invests

`(x)/(2)+(x)/(10)+(x)/(20)+35000=x\\\\35000=x-(x)/(2)-(x)/(10)-(x)/(20)\\\\35000=(20x-10x-2x-x)/(20)\\35000=(7x)/(20)\\\\(35000* 20)/(7)=x\\5000* 20=x\\100000=x`

Answer 2

Answer: $100,000

Explanation:

Land + Stocks + Bonds + Savings = 100%

`(1)/(2)x` + 0.1x +
`(1)/(20)x` + 35,000 = 1.00x

= 0.5x + 0.1x + 0.05x + 35,000 = 1.00x

= 0.65x + 35,000 = 1.00x

35,000 = 0.35x

`(35,000)/(0.35)=(0.35x)/(0.35)`

100,000 = x