Answer: 0.8413
Explanation:
Given : Henry has collected data to find that the typing speeds for the students in a typing class has a normal distribution.
Mean :
Standard deviation :
![\sigma= 4](https://img.qammunity.org/2020/formulas/mathematics/college/gh6v9gt89ga83ol3m6jd8q2afnwhfxffof.png)
Let x be the random variable that represents the typing speeds for the students.
The z-score :-
![z=(x-\mu)/(\sigma)](https://img.qammunity.org/2020/formulas/mathematics/high-school/10fia1p0qwvlz4zhb867kzy3u7bscognwz.png)
For x= 51
![z=(51-47)/(4)=1](https://img.qammunity.org/2020/formulas/mathematics/college/pb94qcjccu3ga8d8ft2fa52robmsodfm0u.png)
Using the standard normal distribution table ,the probability that a randomly selected student has a typing speed of less than 51 words per minute :-
![P(x<51)=P(z<1)\\\\= 0.8413447\approx 0.8413](https://img.qammunity.org/2020/formulas/mathematics/college/xuqtvrblugfnwwd4tyqnop9nhkg4bd774c.png)
Hence, the probability that a randomly selected student has a typing speed of less than 51 words per minute = 0.8413