Question

if Fe(NO3)3 is dissolved in enough water to make exactly 323 ml of solution, what is the molar concentartion of nitrate ion g

Answer 1

The given question is incomplete. the complete question is : If 5.15 g
`Fe(NO_3)_3` is dissolved in enough water to make exactly 323 ml of solution, what is the molar concentartion of nitrate ion.

Answer: The molar concentartion of nitrate ion is 0.195.

Step-by-step explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Given : 5.15 g of
`Fe(NO_3)_3` is dissolved

Volume of solution = 323 ml

`Molarity=(n* 1000)/(V_s)`

where,

n= moles of solute

`Moles=\frac{\text{Given mass}}{\text{Molar mass}}=(5.15g)/(242g/mol)=0.021moles`

`V_s` = volume of solution = 323 ml

`Molarity=(0.021* 1000)/(323)=0.065M`

As 1 M of
`Fe(NO_3)_3` gives 3 M of
`NO_3^-` ions.

Thus 0.065 M of
`Fe(NO_3)_3` gives =
`(3)/(1)* 0.065=0.195M` of
`NO_3^-` ions.

The molar concentartion of nitrate ion is 0.195.