Answer:
The claim that the scores of UT students are less than the US average is wrong
Explanation:
Given : Sample size = 64
Standard deviation = 112
Mean = 505
Average score = 477
To Find : Test the claim that the scores of UT students are less than the US average at the 0.05 level of significance.
Solution:
Sample size = 64
n > 30
So we will use z test
![H_0:\mu \geq 477\\H_a:\mu < 477](https://img.qammunity.org/2020/formulas/mathematics/college/yqqy8zt2fk3qhtypycy5botqq9vw8z8mz1.png)
Formula :
![z=(x-\mu)/((\sigma)/(√(n)))](https://img.qammunity.org/2020/formulas/mathematics/college/koo3vbzftnm9iwwkp1kt7ykogz7qj15wyh.png)
![z=(505-477)/((112)/(√(64)))](https://img.qammunity.org/2020/formulas/mathematics/college/5a7t75dtk6kdw0fak13428nwjr41magjdl.png)
![z=2](https://img.qammunity.org/2020/formulas/mathematics/high-school/eld3nlay2l1xg9h6gy6kaztqc3qwcdokxg.png)
Refer the z table for p value
p value = 0.9772
α=0.05
p value > α
So, we accept the null hypothesis
Hence The claim that the scores of UT students are less than the US average is wrong