Question

If the solubility of copper chloride (CuCl2) is 151 g/dm3, how much copper chloride can be dissolved in 7.8 dm3 of water?

Answer 1

• 1,200 g (rounding to two significant figures).

Step-by-step explanation:

1) Data:

a) S = 151 g/dm³

b) mass = x

c) V = 7.8 dm³³

2) Formula for solubility, S:

• S = mass of solute / volume of solvent.

3) Solution:

• Substitute the data into the formula:

151 g/ dm³ = x / 7.8 dm³

• Solve for x:

x = 151 g/dm³ × 7.8 dm³ = 1,177.8 g.

Round to two significant figures (7.8 dm³ has two sig. fig.): 1,200 g