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Suppose the half-life of a material is 10 days. You have one 1 kg of the material today. How much of the material would you have after 10 days and 20 days, respectively?

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Answer:

0.50 kg of the material would be left after 10 days.

0.25 kg of the material would be left after 20 days.

Explanation:

We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after 10 days and 20 days, respectively.

We will use half life formula.


A=a\cdot((1)/(2))^{(t)/(h)}, where,

A = Amount left after t units of time,

a = Initial amount,

t = Time,

h = Half-life.


A=1\text{ kg}\cdot((1)/(2))^{(10)/(10)}


A=1\text{ kg}\cdot((1)/(2))^(1)


A=1\text{ kg}\cdot(1)/(2)


A=0.5\text{ kg}

Therefore, amount of the material left after 10 days would be 0.5 kg.


A=1\text{ kg}\cdot((1)/(2))^{(20)/(10)}


A=1\text{ kg}\cdot((1)/(2))^(2)


A=1\text{ kg}\cdot(1^2)/(2^2)


A=1\text{ kg}\cdot(1)/(4)


A=0.25\text{ kg}

Therefore, amount of the material left after 20 days would be 0.25 kg.

User Arnaud Weil
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