The Dimensions of triangle are
B=111°, c=8 , b=12
First we will use Cosine Law to Determine , measurement of third side.
![\cos B=(b^2+c^2-a^2)/(2bc)\\\\ \cos 111^(\circ)=((12)^2+(8)^2-a^2)/(2 * 12 * 8)\\\\-0.35836=(144+64-a^2)/(192)\\\\-68.80=208-a^2\\\\a^2=208+68.80\\\\a^2=276.80\\\\a=√(276.80)\\\\a=16.64](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9w00z9irbgqmgxi71c7qf06z7eagno4510.png)
To Form a Triangle ,Sum of two sides of a triangle should be greater than third side.
a=16.64 , b=12, c=8
Angle in front of Side 12 unit has measure 111°, which is an Obtuse Angle.Also Length of Other side is 16.64 unit, so This Angle should also be greater than 111°, But sum of three angles of Triangle is equal to 180°.So, This triangle is not Possible.