Answer:
Step-by-step explanation:
pH = p Ka + log (conjugate base / acid)
5.27 = 4.74 + log base / .01
0.53 = + log base /.01
0.53 = log base/.01
3.38844 = base/.01
conjugate base = .0338844 M.
Required molarity of sodium acetate is .0338844 M
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