Question

The complete mechanism for a reaction is considered to occur in two steps, one of which is slow and the other fast: A + B → C + D slow A + C → E + F fast What is the net chemical equation predicted by this mechanism? A. A + B + C → D + E + F B. A + C → E + F C. A + B → C + D D. 2A + B → D + E + F E. A + B → D + E + F

Answer 1

Answer: The correct answer is D.

Step-by-step explanation:

We are given two reactions which are the two steps of a mechanism:

`A+B\xrightarrow[]{slow}C+D` ......(1)

`A+C\xrightarrow[]{fast}E+F` .......(2)

To determine the net chemical equation, we will simply add the above two equations, we get:

`A+B+A+\\ot{C}\rightarrow \\ot{C}+D+E+F`

`2A+B\rightarrow D+E+F`

The rate of the reaction depends on the slow step of the mechanism, which is:

`Rate=k[A][B]`

Thus, the correct answer is Option D.